PH=2的盐酸与PH=4的盐酸混合后溶液的PH为多少
- 培训职业
- 2025-05-06 06:53:58
PH=2的盐酸[H+]=0.01mol/L
PH=4的盐酸[H+]=0.0001mol/L
如果是等体积混合，混合后,[H+]=(0.01+0.0001)/2=0.00505mol/L
混合后pH=-log,[H+]=-log0.00505=-(-3+log5.05)==-(-3+0.7)=2.3
PH=2的盐酸[H+]=0.01mol/L
PH=4的盐酸[H+]=0.0001mol/L
如果是等体积混合，混合后,[H+]=(0.01+0.0001)/2=0.00505mol/L
混合后pH=-log,[H+]=-log0.00505=-(-3+log5.05)==-(-3+0.7)=2.3
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