二次函数f(x)满足条件：f(0)=3,f(-3)=0,f(-5)=0,，则这个二次函数的解析式是
- 培训职业
- 2025-06-20 07:47:02
因为f(-3) = 0,f(-5) = 0
所以设 f(x) = a(x + 3)(x + 5)
又因为 f(0) = 3
所以 3 = a(0 + 3)(0 + 5)
a = 1/5
所以f(x) = 1/5(x + 3)(x + 5)
即 f(x) = x²/5 + 8x/5 + 3
因为f(-3) = 0,f(-5) = 0
所以设 f(x) = a(x + 3)(x + 5)
又因为 f(0) = 3
所以 3 = a(0 + 3)(0 + 5)
a = 1/5
所以f(x) = 1/5(x + 3)(x + 5)
即 f(x) = x²/5 + 8x/5 + 3
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